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2/10x+5x=11
We move all terms to the left:
2/10x+5x-(11)=0
Domain of the equation: 10x!=0We add all the numbers together, and all the variables
x!=0/10
x!=0
x∈R
5x+2/10x-11=0
We multiply all the terms by the denominator
5x*10x-11*10x+2=0
Wy multiply elements
50x^2-110x+2=0
a = 50; b = -110; c = +2;
Δ = b2-4ac
Δ = -1102-4·50·2
Δ = 11700
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{11700}=\sqrt{900*13}=\sqrt{900}*\sqrt{13}=30\sqrt{13}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-110)-30\sqrt{13}}{2*50}=\frac{110-30\sqrt{13}}{100} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-110)+30\sqrt{13}}{2*50}=\frac{110+30\sqrt{13}}{100} $
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