2/10m+16=4+6/11m

Solution for 2/10m+16=4+6/11m equation:

2/10m+16=4+6/11m

We move all terms to the left:

2/10m+16-(4+6/11m)=0


Domain of the equation: 10m!=0

m!=0/10

m!=0

m∈R



Domain of the equation: 11m)!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

2/10m-(6/11m+4)+16=0

We get rid of parentheses

2/10m-6/11m-4+16=0

We calculate fractions


22m/110m^2+(-60m)/110m^2-4+16=0

We add all the numbers together, and all the variables

22m/110m^2+(-60m)/110m^2+12=0

We multiply all the terms by the denominator


22m+(-60m)+12*110m^2=0

Wy multiply elements

1320m^2+22m+(-60m)=0

We get rid of parentheses

1320m^2+22m-60m=0

We add all the numbers together, and all the variables

1320m^2-38m=0

a = 1320; b = -38; c = 0;
Δ = b2-4ac
Δ = -382-4·1320·0
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-38)-38}{2*1320}=\frac{0}{2640}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-38)+38}{2*1320}=\frac{76}{2640}
=19/660
$