2/10h=35

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Solution for 2/10h=35 equation: 



2/10h=35

We move all terms to the left:

2/10h-(35)=0



Domain of the equation: 10h!=0

h!=0/10

h!=0

h∈R



We multiply all the terms by the denominator


-35*10h+2=0

Wy multiply elements

-350h+2=0

We move all terms containing h to the left, all other terms to the right

-350h=-2

h=-2/-350

h=1/175

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