2/10b=42

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Solution for 2/10b=42 equation: 



2/10b=42

We move all terms to the left:

2/10b-(42)=0



Domain of the equation: 10b!=0

b!=0/10

b!=0

b∈R



We multiply all the terms by the denominator


-42*10b+2=0

Wy multiply elements

-420b+2=0

We move all terms containing b to the left, all other terms to the right

-420b=-2

b=-2/-420

b=1/210

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