2/(z-22)=5/(z-2)

Solution for 2/(z-22)=5/(z-2) equation:

2/(z-22)=5/(z-2)

We move all terms to the left:

2/(z-22)-(5/(z-2))=0


Domain of the equation: (z-22)!=0

We move all terms containing z to the left, all other terms to the right

z!=22

z∈R



Domain of the equation: (z-2))!=0

z∈R


We calculate fractions


2z/((z-22)*(z-2)))+(-(5*(z-22))/((z-22)*(z-2)))=0


We calculate terms in parentheses: -(5*(z-22))/((z-22)*(z-2))), so:

5*(z-22))/((z-22)*(z-2))

We multiply all the terms by the denominator


5*(z-22))

We multiply parentheses

5z+

We add all the numbers together, and all the variables

5z

Back to the equation:

-(5z)


We add all the numbers together, and all the variables

-5z+2z/((z-22)*(z-2)))+(=0

We multiply all the terms by the denominator


-5z*((z-22)*(z-2)))+(+2z=0

We add all the numbers together, and all the variables

2z-5z*((z-22)*(z-2)))+(=0