2/(x+1)=6/(5x-1)

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Solution for 2/(x+1)=6/(5x-1) equation: 



2/(x+1)=6/(5x-1)

We move all terms to the left:

2/(x+1)-(6/(5x-1))=0



Domain of the equation: (x+1)!=0

We move all terms containing x to the left, all other terms to the right

x!=-1

x∈R





Domain of the equation: (5x-1))!=0

x∈R



We calculate fractions


10x/((x+1)*(5x-1)))+(-(6*(x+1))/((x+1)*(5x-1)))=0



We calculate terms in parentheses: -(6*(x+1))/((x+1)*(5x-1))), so:

6*(x+1))/((x+1)*(5x-1))

We multiply all the terms by the denominator


6*(x+1))

We multiply parentheses

6x+

We add all the numbers together, and all the variables

6x

Back to the equation:

-(6x)



We add all the numbers together, and all the variables

-6x+10x/((x+1)*(5x-1)))+(=0

We multiply all the terms by the denominator


-6x*((x+1)*(5x-1)))+(+10x=0

We add all the numbers together, and all the variables

10x-6x*((x+1)*(5x-1)))+(=0

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