2/(n+5)-3/(n+1)

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Solution for 2/(n+5)-3/(n+1) equation: 


D( n )

n+5 = 0

n+1 = 0

n+5 = 0

n+5 = 0

n+5 = 0 // - 5

n = -5

n+1 = 0

n+1 = 0

n+1 = 0 // - 1

n = -1

n in (-oo:-5) U (-5:-1) U (-1:+oo)

2/(n+5)-(3/(n+1)) = 0

2/(n+5)-3*(n+1)^-1 = 0

2/(n+5)-3/(n+1) = 0

(2*(n+1))/((n+5)*(n+1))+(-3*(n+5))/((n+5)*(n+1)) = 0

2*(n+1)-3*(n+5) = 0

-n-13 = 0

(-n-13)/((n+5)*(n+1)) = 0

(-n-13)/((n+5)*(n+1)) = 0 // * (n+5)*(n+1)

-n-13 = 0

-n-13 = 0 // + 13

-n = 13 // * -1

n = -13

n = -13

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