2/(n+3)=-5/(5n-9)

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Solution for 2/(n+3)=-5/(5n-9) equation:


D( n )

n+3 = 0

5*n-9 = 0

n+3 = 0

n+3 = 0

n+3 = 0 // - 3

n = -3

5*n-9 = 0

5*n-9 = 0

5*n-9 = 0 // + 9

5*n = 9 // : 5

n = 9/5

n in (-oo:-3) U (-3:9/5) U (9/5:+oo)

2/(n+3) = -5/(5*n-9) // + -5/(5*n-9)

2/(n+3)-(-5/(5*n-9)) = 0

2/(n+3)+5*(5*n-9)^-1 = 0

2/(n+3)+5/(5*n-9) = 0

(2*(5*n-9))/((n+3)*(5*n-9))+(5*(n+3))/((n+3)*(5*n-9)) = 0

2*(5*n-9)+5*(n+3) = 0

15*n-3 = 0

(15*n-3)/((n+3)*(5*n-9)) = 0

(15*n-3)/((n+3)*(5*n-9)) = 0 // * (n+3)*(5*n-9)

15*n-3 = 0

15*n-3 = 0 // + 3

15*n = 3 // : 15

n = 3/15

n = 1/5

n = 1/5

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