2/(m-5)=3/(m+8)

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Solution for 2/(m-5)=3/(m+8) equation: 



2/(m-5)=3/(m+8)

We move all terms to the left:

2/(m-5)-(3/(m+8))=0



Domain of the equation: (m-5)!=0

We move all terms containing m to the left, all other terms to the right

m!=5

m∈R





Domain of the equation: (m+8))!=0

m∈R



We calculate fractions


2m/((m-5)*(m+8)))+(-(3*(m-5))/((m-5)*(m+8)))=0



We calculate terms in parentheses: -(3*(m-5))/((m-5)*(m+8))), so:

3*(m-5))/((m-5)*(m+8))

We multiply all the terms by the denominator


3*(m-5))

We multiply parentheses

3m+

We add all the numbers together, and all the variables

3m

Back to the equation:

-(3m)



We add all the numbers together, and all the variables

-3m+2m/((m-5)*(m+8)))+(=0

We multiply all the terms by the denominator


-3m*((m-5)*(m+8)))+(+2m=0

We add all the numbers together, and all the variables

2m-3m*((m-5)*(m+8)))+(=0

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