2/(3y)+528=650

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Solution for 2/(3y)+528=650 equation: 



2/(3y)+528=650

We move all terms to the left:

2/(3y)+528-(650)=0



Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R



We add all the numbers together, and all the variables

2/3y-122=0

We multiply all the terms by the denominator


-122*3y+2=0

Wy multiply elements

-366y+2=0

We move all terms containing y to the left, all other terms to the right

-366y=-2

y=-2/-366

y=1/183

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