2/(3x-4)-1=7/(3x-1)

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Solution for 2/(3x-4)-1=7/(3x-1) equation:


D( x )

3*x-4 = 0

3*x-1 = 0

3*x-4 = 0

3*x-4 = 0

3*x-4 = 0 // + 4

3*x = 4 // : 3

x = 4/3

3*x-1 = 0

3*x-1 = 0

3*x-1 = 0 // + 1

3*x = 1 // : 3

x = 1/3

x in (-oo:1/3) U (1/3:4/3) U (4/3:+oo)

2/(3*x-4)-1 = 7/(3*x-1) // - 7/(3*x-1)

2/(3*x-4)-(7/(3*x-1))-1 = 0

2/(3*x-4)-7*(3*x-1)^-1-1 = 0

2/(3*x-4)-7/(3*x-1)-1 = 0

(2*(3*x-1))/((3*x-4)*(3*x-1))+(-7*(3*x-4))/((3*x-4)*(3*x-1))+(-1*(3*x-4)*(3*x-1))/((3*x-4)*(3*x-1)) = 0

2*(3*x-1)-7*(3*x-4)-1*(3*x-4)*(3*x-1) = 0

15*x-9*x^2-15*x-4+26 = 0

22-9*x^2 = 0

(22-9*x^2)/((3*x-4)*(3*x-1)) = 0

(22-9*x^2)/((3*x-4)*(3*x-1)) = 0 // * (3*x-4)*(3*x-1)

22-9*x^2 = 0

-9*x^2 = -22 // : -9

x^2 = 22/9

x^2 = 22/9 // ^ 1/2

abs(x) = (22/9)^(1/2)

x = (22/9)^(1/2) or x = -(22/9)^(1/2)

x in { (22/9)^(1/2), -(22/9)^(1/2) }

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