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2.x^2-21=100
We move all terms to the left:
2.x^2-21-(100)=0
We add all the numbers together, and all the variables
2.x^2-121=0
a = 2.; b = 0; c = -121;
Δ = b2-4ac
Δ = 02-4·2.·(-121)
Δ = 968
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{968}=\sqrt{484*2}=\sqrt{484}*\sqrt{2}=22\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-22\sqrt{2}}{2*2.}=\frac{0-22\sqrt{2}}{4} =-\frac{22\sqrt{2}}{4} =-\frac{11\sqrt{2}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+22\sqrt{2}}{2*2.}=\frac{0+22\sqrt{2}}{4} =\frac{22\sqrt{2}}{4} =\frac{11\sqrt{2}}{2} $
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