2.X2-16X+15=(x-1)

Solution for 2.X2-16X+15=(x-1) equation:

2.X^2-16X+15=(X-1)

We move all terms to the left:

2.X^2-16X+15-((X-1))=0


We calculate terms in parentheses: -((X-1)), so:

(X-1)

We get rid of parentheses

X-1

Back to the equation:

-(X-1)


We get rid of parentheses

2.X^2-16X-X+1+15=0

We add all the numbers together, and all the variables

2.X^2-17X+16=0

a = 2.; b = -17; c = +16;
Δ = b2-4ac
Δ = -172-4·2.·16
Δ = 161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{161}}{2*2.}=\frac{17-\sqrt{161}}{4}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{161}}{2*2.}=\frac{17+\sqrt{161}}{4}
$