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3-(432/(y^2)) = 0
-((x^2+4)*(x^2-4)^2) > 0
sin(x)*sin(x)
sin(x)*ln(x)
(2*x+5)/(3-x)
| 3-(432/y^2)=0 | | Y=.5x-.5 | | 48=-14a^2-58a | | 725.50+10.50=19.50x | | 725+10.50x=10.50x | | 1=4x-1 | | 21b^2-b=10 | | 0.25x+-0.125=0.875+0.5x | | 5(2n-4)=20 | | 0.25x-0.125=0.875+0.5 | | z=1-4i | | y-y+4y-3y-1=18 | | 62+5b-35=36 | | graphf(x)=Ix-2I | | a^2+3ab+b^2=y | | f(x)=Ix-2I | | 4x-2=-7x-44 | | 35x^2=32+36x | | B=c-8a | | -4x*2+8x+44=16 | | 5=r/6=3 | | -720=12x-180 | | 7t+16=5r+2 | | C+c+c+c=4c | | 14x-79=8x-7 | | -7(2p+6)-8=-162 | | 3x=1-1/x | | 5.50x+19=6.75x+9 | | h/-6=3 | | 5(1-8q)=45 | | -3(-5x-7)+x=101 | | -u+281=43 |