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2.5x+1/2x=13.5+4.5x
We move all terms to the left:
2.5x+1/2x-(13.5+4.5x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
2.5x+1/2x-(4.5x+13.5)=0
We get rid of parentheses
2.5x+1/2x-4.5x-13.5=0
We multiply all the terms by the denominator
(2.5x)*2x-(4.5x)*2x-(13.5)*2x+1=0
We add all the numbers together, and all the variables
(+2.5x)*2x-(+4.5x)*2x-(13.5)*2x+1=0
We multiply parentheses
4x^2-8x^2-27x+1=0
We add all the numbers together, and all the variables
-4x^2-27x+1=0
a = -4; b = -27; c = +1;
Δ = b2-4ac
Δ = -272-4·(-4)·1
Δ = 745
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-\sqrt{745}}{2*-4}=\frac{27-\sqrt{745}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+\sqrt{745}}{2*-4}=\frac{27+\sqrt{745}}{-8} $
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