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2.4(3x+2)+0.3x(x+4)=6.6
We move all terms to the left:
2.4(3x+2)+0.3x(x+4)-(6.6)=0
We add all the numbers together, and all the variables
2.4(3x+2)+0.3x(x+4)-6.6=0
We multiply parentheses
0x^2+7.2x+0x+4.8-6.6=0
We add all the numbers together, and all the variables
x^2+8.2x-1.8=0
a = 1; b = 8.2; c = -1.8;
Δ = b2-4ac
Δ = 8.22-4·1·(-1.8)
Δ = 74.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8.2)-\sqrt{74.44}}{2*1}=\frac{-8.2-\sqrt{74.44}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8.2)+\sqrt{74.44}}{2*1}=\frac{-8.2+\sqrt{74.44}}{2} $
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