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2-x=(2(x+1))/3
We move all terms to the left:
2-x-((2(x+1))/3)=0
We add all the numbers together, and all the variables
-1x-((2(x+1))/3)+2=0
We multiply all the terms by the denominator
-1x*3)-((2(x+1))+2*3)=0
We add all the numbers together, and all the variables
-1x*3)-((2(x+1))=0
Wy multiply elements
-3x^2=0
a = -3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-3)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-6}=0$
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