2-t=5-(3/(4t))

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Solution for 2-t=5-(3/(4t)) equation:


D( t )

4*t = 0

4*t = 0

4*t = 0

4*t = 0 // : 4

t = 0

t in (-oo:0) U (0:+oo)

2-t = 5-(3/(4*t)) // - 5-(3/(4*t))

3/(4*t)-t-5+2 = 0

3/4*t^-1-1*t^1-3*t^0 = 0

(3/4*t^0-1*t^2-3*t^1)/(t^1) = 0 // * t^2

t^1*(3/4*t^0-1*t^2-3*t^1) = 0

t^1

3/4-t^2-3*t = 0

3/4-t^2-3*t = 0

DELTA = (-3)^2-(-1*4*(3/4))

DELTA = 12

DELTA > 0

t = (12^(1/2)+3)/(-1*2) or t = (3-12^(1/2))/(-1*2)

t = (2*3^(1/2)+3)/(-2) or t = (3-2*3^(1/2))/(-2)

t in { (2*3^(1/2)+3)/(-2), (3-2*3^(1/2))/(-2)}

t in { (2*3^(1/2)+3)/(-2), (3-2*3^(1/2))/(-2) }

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