2-c=-3(2c+1)2-c=-3(2c+1)

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Solution for 2-c=-3(2c+1)2-c=-3(2c+1) equation: 



2-c=-3(2c+1)2-c=-3(2c+1)

We move all terms to the left:

2-c-(-3(2c+1)2-c)=0

We add all the numbers together, and all the variables

-1c-(-3(2c+1)2-c)+2=0



We calculate terms in parentheses: -(-3(2c+1)2-c), so:

-3(2c+1)2-c

We add all the numbers together, and all the variables

-1c-3(2c+1)2

We multiply parentheses

-1c-12c-6

We add all the numbers together, and all the variables

-13c-6

Back to the equation:

-(-13c-6)



We get rid of parentheses

-1c+13c+6+2=0

We add all the numbers together, and all the variables

12c+8=0

We move all terms containing c to the left, all other terms to the right

12c=-8

c=-8/12

c=-2/3

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