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2-6x=5x(x-1)
We move all terms to the left:
2-6x-(5x(x-1))=0
We calculate terms in parentheses: -(5x(x-1)), so:We get rid of parentheses
5x(x-1)
We multiply parentheses
5x^2-5x
Back to the equation:
-(5x^2-5x)
-5x^2-6x+5x+2=0
We add all the numbers together, and all the variables
-5x^2-1x+2=0
a = -5; b = -1; c = +2;
Δ = b2-4ac
Δ = -12-4·(-5)·2
Δ = 41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{41}}{2*-5}=\frac{1-\sqrt{41}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{41}}{2*-5}=\frac{1+\sqrt{41}}{-10} $
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