2-6(m+1)=4(2-3m)=6

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Solution for 2-6(m+1)=4(2-3m)=6 equation: 



2-6(m+1)=4(2-3m)=6

We move all terms to the left:

2-6(m+1)-(4(2-3m))=0

We add all the numbers together, and all the variables

-6(m+1)-(4(-3m+2))+2=0

We multiply parentheses

-6m-(4(-3m+2))-6+2=0



We calculate terms in parentheses: -(4(-3m+2)), so:

4(-3m+2)

We multiply parentheses

-12m+8

Back to the equation:

-(-12m+8)



We add all the numbers together, and all the variables

-6m-(-12m+8)-4=0

We get rid of parentheses

-6m+12m-8-4=0

We add all the numbers together, and all the variables

6m-12=0

We move all terms containing m to the left, all other terms to the right

6m=12

m=12/6

m=2

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