2-6(m+1)=4(2-3m)+6

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Solution for 2-6(m+1)=4(2-3m)+6 equation: 



2-6(m+1)=4(2-3m)+6

We move all terms to the left:

2-6(m+1)-(4(2-3m)+6)=0

We add all the numbers together, and all the variables

-6(m+1)-(4(-3m+2)+6)+2=0

We multiply parentheses

-6m-(4(-3m+2)+6)-6+2=0



We calculate terms in parentheses: -(4(-3m+2)+6), so:

4(-3m+2)+6

We multiply parentheses

-12m+8+6

We add all the numbers together, and all the variables

-12m+14

Back to the equation:

-(-12m+14)



We add all the numbers together, and all the variables

-6m-(-12m+14)-4=0

We get rid of parentheses

-6m+12m-14-4=0

We add all the numbers together, and all the variables

6m-18=0

We move all terms containing m to the left, all other terms to the right

6m=18

m=18/6

m=3

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