2-5x=1/5(25-40x)

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Solution for 2-5x=1/5(25-40x) equation: 



2-5x=1/5(25-40x)

We move all terms to the left:

2-5x-(1/5(25-40x))=0



Domain of the equation: 5(25-40x))!=0

x∈R



We add all the numbers together, and all the variables

-5x-(1/5(-40x+25))+2=0

We multiply all the terms by the denominator


-5x*5(-40x+25))-(1+2*5(-40x+25))=0

Wy multiply elements

-25x^2(-+10x(-=0

We use the square of the difference formula

-25x^2(-10x(-=0

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