2-5(3-3y)=-7-4(2+y)

Solution for 2-5(3-3y)=-7-4(2+y) equation:

2-5(3-3y)=-7-4(2+y)

We move all terms to the left:

2-5(3-3y)-(-7-4(2+y))=0

We add all the numbers together, and all the variables

-5(-3y+3)-(-7-4(y+2))+2=0

We multiply parentheses

15y-(-7-4(y+2))-15+2=0


We calculate terms in parentheses: -(-7-4(y+2)), so:

-7-4(y+2)

determiningTheFunctionDomain
-4(y+2)-7

We multiply parentheses

-4y-8-7

We add all the numbers together, and all the variables

-4y-15

Back to the equation:

-(-4y-15)


We add all the numbers together, and all the variables

15y-(-4y-15)-13=0

We get rid of parentheses

15y+4y+15-13=0

We add all the numbers together, and all the variables

19y+2=0

We move all terms containing y to the left, all other terms to the right

19y=-2

y=-2/19

y=-2/19