2-5(3-2x)=-7+4(2+x)

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Solution for 2-5(3-2x)=-7+4(2+x) equation: 



2-5(3-2x)=-7+4(2+x)

We move all terms to the left:

2-5(3-2x)-(-7+4(2+x))=0

We add all the numbers together, and all the variables

-5(-2x+3)-(-7+4(x+2))+2=0

We multiply parentheses

10x-(-7+4(x+2))-15+2=0



We calculate terms in parentheses: -(-7+4(x+2)), so:

-7+4(x+2)

determiningTheFunctionDomain
4(x+2)-7

We multiply parentheses

4x+8-7

We add all the numbers together, and all the variables

4x+1

Back to the equation:

-(4x+1)



We add all the numbers together, and all the variables

10x-(4x+1)-13=0

We get rid of parentheses

10x-4x-1-13=0

We add all the numbers together, and all the variables

6x-14=0

We move all terms containing x to the left, all other terms to the right

6x=14

x=14/6

x=2+1/3

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