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2-5(2x-3)=4(3-4x)
We move all terms to the left:
2-5(2x-3)-(4(3-4x))=0
We add all the numbers together, and all the variables
-5(2x-3)-(4(-4x+3))+2=0
We multiply parentheses
-10x-(4(-4x+3))+15+2=0
We calculate terms in parentheses: -(4(-4x+3)), so:We add all the numbers together, and all the variables
4(-4x+3)
We multiply parentheses
-16x+12
Back to the equation:
-(-16x+12)
-10x-(-16x+12)+17=0
We get rid of parentheses
-10x+16x-12+17=0
We add all the numbers together, and all the variables
6x+5=0
We move all terms containing x to the left, all other terms to the right
6x=-5
x=-5/6
x=-5/6
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