2-4(x+2)=16+2(4+3x)

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Solution for 2-4(x+2)=16+2(4+3x) equation: 



2-4(x+2)=16+2(4+3x)

We move all terms to the left:

2-4(x+2)-(16+2(4+3x))=0

We add all the numbers together, and all the variables

-4(x+2)-(16+2(3x+4))+2=0

We multiply parentheses

-4x-(16+2(3x+4))-8+2=0



We calculate terms in parentheses: -(16+2(3x+4)), so:

16+2(3x+4)

determiningTheFunctionDomain
2(3x+4)+16

We multiply parentheses

6x+8+16

We add all the numbers together, and all the variables

6x+24

Back to the equation:

-(6x+24)



We add all the numbers together, and all the variables

-4x-(6x+24)-6=0

We get rid of parentheses

-4x-6x-24-6=0

We add all the numbers together, and all the variables

-10x-30=0

We move all terms containing x to the left, all other terms to the right

-10x=30

x=30/-10

x=-3

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