2-3/4x=1/8x

Solution for 2-3/4x=1/8x equation:

2-3/4x=1/8x

We move all terms to the left:

2-3/4x-(1/8x)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 8x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-3/4x-(+1/8x)+2=0

We get rid of parentheses

-3/4x-1/8x+2=0

We calculate fractions


(-24x)/32x^2+(-4x)/32x^2+2=0

We multiply all the terms by the denominator


(-24x)+(-4x)+2*32x^2=0

Wy multiply elements

64x^2+(-24x)+(-4x)=0

We get rid of parentheses

64x^2-24x-4x=0

We add all the numbers together, and all the variables

64x^2-28x=0

a = 64; b = -28; c = 0;
Δ = b2-4ac
Δ = -282-4·64·0
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-28}{2*64}=\frac{0}{128}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+28}{2*64}=\frac{56}{128}
=7/16
$