2-3/4k=1/6(3n-5)

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Solution for 2-3/4k=1/6(3n-5) equation: 


x in (-oo:+oo)

2-((3/4)*k) = (1/6)*(3*n-5) // - (1/6)*(3*n-5)

2-((1/6)*(3*n-5))-((3/4)*k) = 0

(-1/6)*(3*n-5)+(-3/4)*k+2 = 0

(-3*k)/4-1/6*(3*n-5)+2 = 0

(-1/6*4*(3*n-5))/4+(-3*k)/4+(2*4)/4 = 0

2*4-1/6*4*(3*n-5)-3*k = 0

10/3-3*k-2*n+8 = 0

34/3-3*k-2*n = 0

(34/3-3*k-2*n)/4 = 0

(34/3-3*k-2*n)/4 = 0 // * 4

34/3-3*k-2*n = 0

x belongs to the empty set

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