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2-3(x-1)=5-2(x-3)
We move all terms to the left:
2-3(x-1)-(5-2(x-3))=0
We multiply parentheses
-3x-(5-2(x-3))+3+2=0
We calculate terms in parentheses: -(5-2(x-3)), so:We add all the numbers together, and all the variables
5-2(x-3)
determiningTheFunctionDomain -2(x-3)+5
We multiply parentheses
-2x+6+5
We add all the numbers together, and all the variables
-2x+11
Back to the equation:
-(-2x+11)
-3x-(-2x+11)+5=0
We get rid of parentheses
-3x+2x-11+5=0
We add all the numbers together, and all the variables
-1x-6=0
We move all terms containing x to the left, all other terms to the right
-x=6
x=6/-1
x=-6
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