2-3(x+2)=4+2(x+1)

Solution for 2-3(x+2)=4+2(x+1) equation:

2-3(x+2)=4+2(x+1)

We move all terms to the left:

2-3(x+2)-(4+2(x+1))=0

We multiply parentheses

-3x-(4+2(x+1))-6+2=0


We calculate terms in parentheses: -(4+2(x+1)), so:

4+2(x+1)

determiningTheFunctionDomain
2(x+1)+4

We multiply parentheses

2x+2+4

We add all the numbers together, and all the variables

2x+6

Back to the equation:

-(2x+6)


We add all the numbers together, and all the variables

-3x-(2x+6)-4=0

We get rid of parentheses

-3x-2x-6-4=0

We add all the numbers together, and all the variables

-5x-10=0

We move all terms containing x to the left, all other terms to the right

-5x=10

x=10/-5

x=-2