2-3(i+8)=-13-1/3(9i+27)

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Solution for 2-3(i+8)=-13-1/3(9i+27) equation: 



2-3(i+8)=-13-1/3(9i+27)

We move all terms to the left:

2-3(i+8)-(-13-1/3(9i+27))=0



Domain of the equation: 3(9i+27))!=0

i∈R



We multiply parentheses

-3i-(-13-1/3(9i+27))-24+2=0

We multiply all the terms by the denominator


-3i*3(9i+27))-(-24*3(9i+27))+2*3(9i-13-1+27))=0

We add all the numbers together, and all the variables

-3i*3(9i+27))-(-24*3(9i+27))+2*3(9i+13))=0

We add all the numbers together, and all the variables

-3i*3(9i+27))-(-24*3(9i+27))+2*3(9i=0

Wy multiply elements

-9i^2(9-216i^2(9=0

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