2-2s=(3/4s)+13

Solution for 2-2s=(3/4s)+13 equation:

2-2s=(3/4s)+13

We move all terms to the left:

2-2s-((3/4s)+13)=0


Domain of the equation: 4s)+13)!=0

s!=0/1

s!=0

s∈R


We add all the numbers together, and all the variables

-2s-((+3/4s)+13)+2=0

We multiply all the terms by the denominator


-2s*4s)+13)-((+2*4s)+13)+3=0

Wy multiply elements

-8s^2+8s=0

a = -8; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·(-8)·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*-8}=\frac{-16}{-16}
=1
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*-8}=\frac{0}{-16}
=0
$