2-2/3(x+1)=6x+10

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Solution for 2-2/3(x+1)=6x+10 equation: 



2-2/3(x+1)=6x+10

We move all terms to the left:

2-2/3(x+1)-(6x+10)=0



Domain of the equation: 3(x+1)!=0

x∈R



We get rid of parentheses

-2/3(x+1)-6x-10+2=0

We multiply all the terms by the denominator


-6x*3(x+1)-10*3(x+1)+2*3(x+1)-2=0

Wy multiply elements

-18x^2(x-30x(x+6x(x-2=0

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