2-2(g+3)=3(3g+2)-5

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Solution for 2-2(g+3)=3(3g+2)-5 equation: 



2-2(g+3)=3(3g+2)-5

We move all terms to the left:

2-2(g+3)-(3(3g+2)-5)=0

We multiply parentheses

-2g-(3(3g+2)-5)-6+2=0



We calculate terms in parentheses: -(3(3g+2)-5), so:

3(3g+2)-5

We multiply parentheses

9g+6-5

We add all the numbers together, and all the variables

9g+1

Back to the equation:

-(9g+1)



We add all the numbers together, and all the variables

-2g-(9g+1)-4=0

We get rid of parentheses

-2g-9g-1-4=0

We add all the numbers together, and all the variables

-11g-5=0

We move all terms containing g to the left, all other terms to the right

-11g=5

g=5/-11

g=-5/11

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