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2-15n=5n(-3n+2)
We move all terms to the left:
2-15n-(5n(-3n+2))=0
We calculate terms in parentheses: -(5n(-3n+2)), so:We get rid of parentheses
5n(-3n+2)
We multiply parentheses
-15n^2+10n
Back to the equation:
-(-15n^2+10n)
15n^2-10n-15n+2=0
We add all the numbers together, and all the variables
15n^2-25n+2=0
a = 15; b = -25; c = +2;
Δ = b2-4ac
Δ = -252-4·15·2
Δ = 505
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-\sqrt{505}}{2*15}=\frac{25-\sqrt{505}}{30} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+\sqrt{505}}{2*15}=\frac{25+\sqrt{505}}{30} $
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