2-1/4(12-8x)+2x=4x+15-(x+3)

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Solution for 2-1/4(12-8x)+2x=4x+15-(x+3) equation: 



2-1/4(12-8x)+2x=4x+15-(x+3)

We move all terms to the left:

2-1/4(12-8x)+2x-(4x+15-(x+3))=0



Domain of the equation: 4(12-8x)!=0

x∈R



We add all the numbers together, and all the variables

-1/4(-8x+12)+2x-(4x+15-(x+3))+2=0

We add all the numbers together, and all the variables

2x-1/4(-8x+12)-(4x+15-(x+3))+2=0

We multiply all the terms by the denominator


2x*4(-8x+12)-((4x+15-(x+3)))*4(-8x+12)+2*4(-8x+12)-1=0



We calculate terms in parentheses: -((4x+15-(x+3)))*4(-8x+12), so:

(4x+15-(x+3)))*4(-8x+12

We add all the numbers together, and all the variables

-8x+(4x+15-(x+3)))*4(+12

Back to the equation:

-(-8x+(4x+15-(x+3)))*4(+12)



We add all the numbers together, and all the variables

2x*4(-8x+12)-(-8x+(4x+15-(x+3)))*412+2*4(-8x+12)-1=0

Wy multiply elements

8x^2(--(-8x+(4x+15-(x+3)))*412+8x(--1=0

We use the square of the difference formula

8x^2(+(-8x+(4x+15-(x+3)))*412+8x(+1=0

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