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2-1/3n=3+1/4n
We move all terms to the left:
2-1/3n-(3+1/4n)=0
Domain of the equation: 3n!=0
n!=0/3
n!=0
n∈R
Domain of the equation: 4n)!=0We add all the numbers together, and all the variables
n!=0/1
n!=0
n∈R
-1/3n-(1/4n+3)+2=0
We get rid of parentheses
-1/3n-1/4n-3+2=0
We calculate fractions
(-4n)/12n^2+(-3n)/12n^2-3+2=0
We add all the numbers together, and all the variables
(-4n)/12n^2+(-3n)/12n^2-1=0
We multiply all the terms by the denominator
(-4n)+(-3n)-1*12n^2=0
Wy multiply elements
-12n^2+(-4n)+(-3n)=0
We get rid of parentheses
-12n^2-4n-3n=0
We add all the numbers together, and all the variables
-12n^2-7n=0
a = -12; b = -7; c = 0;
Δ = b2-4ac
Δ = -72-4·(-12)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-7}{2*-12}=\frac{0}{-24} =0 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+7}{2*-12}=\frac{14}{-24} =-7/12 $
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