2-(y+5)=-2(3y-1)+6y

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Solution for 2-(y+5)=-2(3y-1)+6y equation: 



2-(y+5)=-2(3y-1)+6y

We move all terms to the left:

2-(y+5)-(-2(3y-1)+6y)=0

We get rid of parentheses

-y-(-2(3y-1)+6y)-5+2=0



We calculate terms in parentheses: -(-2(3y-1)+6y), so:

-2(3y-1)+6y

We add all the numbers together, and all the variables

6y-2(3y-1)

We multiply parentheses

6y-6y+2

We add all the numbers together, and all the variables

2

Back to the equation:

-(2)



We add all the numbers together, and all the variables

-1y-5=0

We move all terms containing y to the left, all other terms to the right

-y=5

y=5/-1

y=-5

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