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2-(3x/x-10)=x
We move all terms to the left:
2-(3x/x-10)-(x)=0
Domain of the equation: x-10)!=0We add all the numbers together, and all the variables
x∈R
-1x-(3x/x-10)+2=0
We get rid of parentheses
-1x-3x/x+10+2=0
We multiply all the terms by the denominator
-1x*x-3x+10*x+2*x=0
We add all the numbers together, and all the variables
9x-1x*x=0
Wy multiply elements
-1x^2+9x=0
a = -1; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·(-1)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*-1}=\frac{-18}{-2} =+9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*-1}=\frac{0}{-2} =0 $
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