2-(3n+5)=3(n-1)

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Solution for 2-(3n+5)=3(n-1) equation: 



2-(3n+5)=3(n-1)

We move all terms to the left:

2-(3n+5)-(3(n-1))=0

We get rid of parentheses

-3n-(3(n-1))-5+2=0



We calculate terms in parentheses: -(3(n-1)), so:

3(n-1)

We multiply parentheses

3n-3

Back to the equation:

-(3n-3)



We add all the numbers together, and all the variables

-3n-(3n-3)-3=0

We get rid of parentheses

-3n-3n+3-3=0

We add all the numbers together, and all the variables

-6n=0

n=0/-6

n=0

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