2-(2t+1)=4(t+2)

Solution for 2-(2t+1)=4(t+2) equation:

2-(2t+1)=4(t+2)

We move all terms to the left:

2-(2t+1)-(4(t+2))=0

We get rid of parentheses

-2t-(4(t+2))-1+2=0


We calculate terms in parentheses: -(4(t+2)), so:

4(t+2)

We multiply parentheses

4t+8

Back to the equation:

-(4t+8)


We add all the numbers together, and all the variables

-2t-(4t+8)+1=0

We get rid of parentheses

-2t-4t-8+1=0

We add all the numbers together, and all the variables

-6t-7=0

We move all terms containing t to the left, all other terms to the right

-6t=7

t=7/-6

t=-1+1/6