2,8y+3(1-3,2y)=5+2(3,4+y)

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Solution for 2,8y+3(1-3,2y)=5+2(3,4+y) equation: 



2.8y+3(1-3.2y)=5+2(3.4+y)

We move all terms to the left:

2.8y+3(1-3.2y)-(5+2(3.4+y))=0

We add all the numbers together, and all the variables

2.8y+3(-3.2y+1)-(5+2(y+3.4))=0

We multiply parentheses

2.8y-9y-(5+2(y+3.4))+3=0



We calculate terms in parentheses: -(5+2(y+3.4)), so:

5+2(y+3.4)

determiningTheFunctionDomain
2(y+3.4)+5

We multiply parentheses

2y+6.8+5

We add all the numbers together, and all the variables

2y+11.8

Back to the equation:

-(2y+11.8)



We add all the numbers together, and all the variables

-6.2y-(2y+11.8)+3=0

We get rid of parentheses

-6.2y-2y-11.8+3=0

We add all the numbers together, and all the variables

-8.2y-8.8=0

We move all terms containing y to the left, all other terms to the right

-8.2y=8.8

y=8.8/-8.2

y=-1+0.6/8.2

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