2,50x=(x+12)X0,50

Solution for 2,50x=(x+12)X0,50 equation:

2.50x=(x+12)x0.50

We move all terms to the left:

2.50x-((x+12)x0.50)=0


We calculate terms in parentheses: -((x+12)x0.50), so:

(x+12)x0.50

We multiply parentheses

x^2+12x

Back to the equation:

-(x^2+12x)


We get rid of parentheses

-x^2+2.50x-12x=0

We add all the numbers together, and all the variables

-1x^2-9.5x=0

a = -1; b = -9.5; c = 0;
Δ = b2-4ac
Δ = -9.52-4·(-1)·0
Δ = 90.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9.5)-\sqrt{90.25}}{2*-1}=\frac{9.5-\sqrt{90.25}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9.5)+\sqrt{90.25}}{2*-1}=\frac{9.5+\sqrt{90.25}}{-2}
$