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2+x(2+x+x)=5(5+7)
We move all terms to the left:
2+x(2+x+x)-(5(5+7))=0
We add all the numbers together, and all the variables
x(2x+2)+2-(512)=0
We add all the numbers together, and all the variables
x(2x+2)-510=0
We multiply parentheses
2x^2+2x-510=0
a = 2; b = 2; c = -510;
Δ = b2-4ac
Δ = 22-4·2·(-510)
Δ = 4084
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4084}=\sqrt{4*1021}=\sqrt{4}*\sqrt{1021}=2\sqrt{1021}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{1021}}{2*2}=\frac{-2-2\sqrt{1021}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{1021}}{2*2}=\frac{-2+2\sqrt{1021}}{4} $
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