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2+5(x-16)=4x(2x+3)
We move all terms to the left:
2+5(x-16)-(4x(2x+3))=0
We multiply parentheses
5x-(4x(2x+3))-80+2=0
We calculate terms in parentheses: -(4x(2x+3)), so:We add all the numbers together, and all the variables
4x(2x+3)
We multiply parentheses
8x^2+12x
Back to the equation:
-(8x^2+12x)
5x-(8x^2+12x)-78=0
We get rid of parentheses
-8x^2+5x-12x-78=0
We add all the numbers together, and all the variables
-8x^2-7x-78=0
a = -8; b = -7; c = -78;
Δ = b2-4ac
Δ = -72-4·(-8)·(-78)
Δ = -2447
Delta is less than zero, so there is no solution for the equation
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