2+5(3t-1)=1+4(t-2)

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Solution for 2+5(3t-1)=1+4(t-2) equation: 



2+5(3t-1)=1+4(t-2)

We move all terms to the left:

2+5(3t-1)-(1+4(t-2))=0

We multiply parentheses

15t-(1+4(t-2))-5+2=0



We calculate terms in parentheses: -(1+4(t-2)), so:

1+4(t-2)

determiningTheFunctionDomain
4(t-2)+1

We multiply parentheses

4t-8+1

We add all the numbers together, and all the variables

4t-7

Back to the equation:

-(4t-7)



We add all the numbers together, and all the variables

15t-(4t-7)-3=0

We get rid of parentheses

15t-4t+7-3=0

We add all the numbers together, and all the variables

11t+4=0

We move all terms containing t to the left, all other terms to the right

11t=-4

t=-4/11

t=-4/11

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