2+4r-10+6r=2(5r-4)

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Solution for 2+4r-10+6r=2(5r-4) equation: 



2+4r-10+6r=2(5r-4)

We move all terms to the left:

2+4r-10+6r-(2(5r-4))=0

We add all the numbers together, and all the variables

10r-(2(5r-4))-8=0



We calculate terms in parentheses: -(2(5r-4)), so:

2(5r-4)

We multiply parentheses

10r-8

Back to the equation:

-(10r-8)



We get rid of parentheses

10r-10r+8-8=0

We add all the numbers together, and all the variables

=0

r=0/1

r=0

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