2+4/5y=7+2/5y

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Solution for 2+4/5y=7+2/5y equation: 



2+4/5y=7+2/5y

We move all terms to the left:

2+4/5y-(7+2/5y)=0



Domain of the equation: 5y!=0

y!=0/5

y!=0

y∈R





Domain of the equation: 5y)!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

4/5y-(2/5y+7)+2=0

We get rid of parentheses

4/5y-2/5y-7+2=0

We multiply all the terms by the denominator


-7*5y+2*5y+4-2=0

We add all the numbers together, and all the variables

-7*5y+2*5y+2=0

Wy multiply elements

-35y+10y+2=0

We add all the numbers together, and all the variables

-25y+2=0

We move all terms containing y to the left, all other terms to the right

-25y=-2

y=-2/-25

y=2/25

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