2+3y/7-y-4/3=y/2

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Solution for 2+3y/7-y-4/3=y/2 equation: 


y in (-oo:+oo)

(3*y)/7-y-(4/3)+2 = y/2 // - y/2

(3*y)/7-y-(y/2)-(4/3)+2 = 0

(3*y)/7-y-(y/2)-4/3+2 = 0

2/3-15/14*y = 0 // - 2/3

-15/14*y = -2/3 // : -15/14

y = -2/3/(-15/14)

y = 28/45

y = 28/45

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